设A={1,2,3,4,5},A上二元关系R={〈1,2〉,〈3,4〉,〈2,2〉},S={〈2,4〉,〈3,1〉,〈4,2〉},则S-1R-1的运算结果是( )
·{〈4,1〉,〈2,3〉,〈4,2〉}
·{〈2,4〉,〈2,3〉,〈4,2〉}
·{〈4,1〉,〈2,3〉,〈2,4〉}
·{〈2,2〉,〈3,1〉,〈4,4〉}